A mass m of material exists in its solid stat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $m$ be the total mass of the material, $L$ be the latent heat of fusion, and $s$ be the specific heat of the liquid.In Process-$1$, the energy

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(A) Let $m$ be the total mass of the material, $L$ be the latent heat of fusion, and $s$ be the specific heat of the liquid.In Process-$1$, the energy $Q$ melts $\frac{2}{3}$ of the mass:$Q = \frac{2}{3} m L$ --- (Equation $1$)In Process-$2$, an additional energy $Q$ is added. This energy first melts the remaining $\frac{1}{3}$ of the solid and then raises the temperature of the entire liquid mass $m$ from $0^\circ C$ to $40^\circ C$:$Q = \frac{1}{3} m L + m s (40 - 0)$$Q = \frac{1}{3} m L + 40 m s$ --- (Equation $2$)Equating Equation $1$ and Equation $2$:$\frac{2}{3} m L = \frac{1}{3} m L + 40 m s$$\frac{1}{3} m L = 40 m s$$\frac{L}{s} = 40 	imes 3 = 120$Thus, the ratio of the latent heat of fusion to the specific heat of the liquid is $120$.

Similar Questions

The variation of density of water with temperature is represented by the

Find the quantity of heat required to convert $40 \; g$ of ice at $-20^{\circ} C$ into water at $20^{\circ} C$. Given $L_{\text{ice}} = 0.336 \times 10^6 \; J/kg$,specific heat of ice $= 2100 \; J/kg \cdot K$,and specific heat of water $= 4200 \; J/kg \cdot K$. (in $; J$)

$22320 \ cal$ of heat is supplied to $100 \ g$ of ice at $0^{\circ} C$. If the latent heat of fusion of ice is $80 \ cal \ g^{-1}$ and latent heat of vaporization of water is $540 \ cal \ g^{-1}$,the final amount of water thus obtained and its temperature respectively are:

'Stem correction' in platinum resistance thermometers is eliminated by the use of

Heat is being supplied at a constant rate to a sphere of ice which is melting at the rate of $0.1 \, g/s$. It melts completely in $100 \, s$. The rate of rise of temperature thereafter will be ........ $^\circ C/s$ (Assume no loss of heat.)

Vedclass Test Series

Exam Paper Generator

Online Exam Module